Question

s] from a circular Sheet of radius
18 cm, two cirles of radius 4.5 cm and rectangle of length 4 cm and breadth 1 cm are removed .find the area of the remaining sheet
​

Answer 1

r=14 cm

total area= πr²

=22/7*196=616 cm²

r2= 3.5 cm

area of the small circles= 2*πr²=2*12.25*22/7=77 cm²

length of rectangle=3

breadth=1

area =lb=3 cm²

area of the small circles+area of rectangle=77+3=80 cm²

remaining area=616-80=536 cm²

Answer 2

Answer:

Radius of Circular Sheet= 18 cm

Area of circular sheet= πr²

                                   = $\frac{22}{7}X18X18$ $cm^2$

                                   

Radius of smaller circles = 4.5cm

Area of two small circulars= 2πr² = $2(\frac{22}{7} )(4.5)(4.5)$ $cm^2$

Area of rectangle = (length)(breadth) = (4)(1)=$4 cm^2$

Remaining area=

                                    $\frac{22}{7}X18X18 - \frac{22}{7}X2X4.5X4.5-4\\ \\\frac{22}{7}[324-40.5]-4 \\ \\\frac{22}{7}[283.5]-4\\ \\\frac{6237}{7} -4\\ \\ 891-4=887 cm^2$