s in the given figure, O is the centre of the
aide IF angleACB = 50°, find angleOAB.
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answer :-
∠ AOB = 40°
Step-by-step explanation:
We know that the angle subtended by an arc of a circle at the centre is double the angle subtended by the arc at any point on the circumference.
So we get
∠AOB = 2 ∠ACB
It is given that ∠ACB = 50°
By substituting
∠AOB = 2 × 50°
By multiplication
∠AOB = 100° …… (1)
Consider △ OAB
We know that the radius of the circle are equal
OA = OB
Base angles of an isosceles triangle are equal
So we get
∠OAB = ∠OBA ……. (2)
Using the angle sum property
∠AOB + ∠OAB + ∠OBA = 180°
Using equations (1) and (2) we get
100° + 2 ∠OAB = 180°
By subtraction
2 ∠OAB = 180° – 100°
So we get
2 ∠OAB = 80°
By division
∠OAB = 40°
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