Math, asked by kuldeepsachdev7496, 1 year ago

S is any point on triangle pqr show that pq+pr>2ps

Answers

Answered by sangeeta84
2

Solution of this question :-

• GIVEN:- In Δ PQR, S is any point on the side QR.

• TO SHOW:- PQ + PR + QR > 2ps

• PROVE:- In ΔPQS

Sum of any two sides is greater than the third side.

So, PQ + QS > PS ......(1)

In ΔPSR

Sum of any two sides is greater than the third side.

So, PR + SR > PS ...(2)

Adding equations (1) and (2)

PQ + PR + QS + SR > PS + PS

PQ + PR + QR > 2PS   [ QS + SR = QR]

I hope this will help you please mark my answer as brainliest answer.

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