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(Jņ a ABC, LA CB = 90° LABC = 0, BC=12
unite, AB= 13 units. Find din ê cos o, sin (90-0),
ccas 90 - 0)
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Δ ABC is a right angled triangle AB2 = AC2 + BC2 (29)2 = AC2 + (21)2 841 = AC2 + 441 AC2 = 400 or AC = 20 Find sin θ and cos θ: sinθ = AC/AB = 20/29 cosθ = BC/AB = 21/29 Now: LHS = cos2θ – sin2θ = (21/29)2 – (20/29)2 = 41/841 = RHSRead more on Sarthaks.com - https://www.sarthaks.com/710885/in-a-abc-in-which-c-90-abc-bc-21-units-ab-29-units
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