Question

◍ sσlvє thє fσllσwíng:-
$1. \: p(8 - 2) = 12$
$2. \: ( - 5)(z + 2) = - 4$
$3. \: 6(k - 3) = 8$

Answer 1

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$1. \: p(8 - 2) = 12$

$\therefore p(6) = 12$

$\therefore p = 12 \div 6$

$\green \Longrightarrow \blue{\fbox{p = 2}}$

$2. \: ( - 5)(z + 2) = - 4$

$\therefore - 5z - 10 = - 4$

$\therefore - 5z = - 4 + 10$

$\therefore - 5z = 6$

$\green \Longrightarrow \blue{ \boxed{ z = - \frac{6}{5} }}$

$3. \: 6(k - 3) = 8$

$\therefore 6k - 18 = 8$

$\therefore 6k = 8 - 18$

$\therefore 6k = - 10$

$\therefore k = - \frac{10}{6}$

$\green \Longrightarrow \blue{ \boxed{ k = - \frac{5}{3} }}$

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Answer 2

Figure : Anode and Cathode Currents

A useful mnemonic is ACID : Anode Current Into Device. By current we mean the positive conventional current. Since electrons are negatively charged, positive current flowing in is the same as electrons flowing out.

That’s essentially all there is to it.