Question

◍ sσlvє thє fσllσwíng:-
$1. \: p(8 - 2) = 12$
$2. \: ( - 5)(z + 2) = - 4$
$3. \: 6(k - 3) = 8$

Answer 1

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$1. \: p(8 - 2) = 12$

$\therefore p(6) = 12$

$\therefore p = 12 \div 6$

$\green \Longrightarrow \blue{\fbox{p = 2}}$

$2. \: ( - 5)(z + 2) = - 4$

$\therefore - 5z - 10 = - 4$

$\therefore - 5z = - 4 + 10$

$\therefore - 5z = 6$

$\green \Longrightarrow \blue{ \boxed{ z = - \frac{6}{5} }}$

$3. \: 6(k - 3) = 8$

$\therefore 6k - 18 = 8$

$\therefore 6k = 8 - 18$

$\therefore 6k = - 10$

$\therefore k = - \frac{10}{6}$

$\green \Longrightarrow \blue{ \boxed{ k = - \frac{5}{3} }}$

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Answer 2

p(8-2)=12
8p-2p=12
6p=12
p=12/6
p=2




2. -5(z+2)=-4
-5z-10=-4
-5z=-4+10
-5z=6
z=-(6/5)


3. 6(k-3)=8
6k-18=7
6k=7+18
6k=25
k=25/6