S n T are points of sides PR and QR such that angle P is equal to Angle RDD show that Triangle RPQ is similar to Triangle RTS
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In △RPQ and △RTS
∠R is common
∠RTS=∠P (Given)
∠PRQ=∠TRS=∠R (Common)
Hence, By AA criterion of similarity, △RPQ∼△RTS [henceproved]
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