S......O.....L....V......E
class 10
solve in any method
Attachments:
Answers
Answered by
2
EQ :-1 x 1 :- 2 / √ X + 3 / 1√ Y = 2 / 1
EQ :-2 x 1 /2 :- 2 / √ X - 9 / 2 √ Y = -1 / 2
( - ) ( + ) (+)
--------------------------------------------
0 + 15 / 2 √ Y = 5 / 2
15 / 2 √Y = 5 / 2
√ Y = 5 / 2 X 2 / 15 = 1 / 3
√Y = 1 / 3
2 / √X + 3 / √ Y = 2
2 / √ X + 9 = 2
2 / √ X = 2 - 9
2 / √ X = - 7
√X = 2 / -7
√ X = - 2 / 7.
Hope this helps you.☺☺☺
EQ :-2 x 1 /2 :- 2 / √ X - 9 / 2 √ Y = -1 / 2
( - ) ( + ) (+)
--------------------------------------------
0 + 15 / 2 √ Y = 5 / 2
15 / 2 √Y = 5 / 2
√ Y = 5 / 2 X 2 / 15 = 1 / 3
√Y = 1 / 3
2 / √X + 3 / √ Y = 2
2 / √ X + 9 = 2
2 / √ X = 2 - 9
2 / √ X = - 7
√X = 2 / -7
√ X = - 2 / 7.
Hope this helps you.☺☺☺
Answered by
1
hey !!
here the ans is....
2/√x+ 3/√y =2 equ....1
4/√x +9/√y=-1 equ...2
let 1/√x=p and 1/√y=q
putting this in equ..1 and 2,we get..
2p+3q=2 equ....3
4p-9q= -1 equ...4
multiplying equ 3 by equ 2 and subtracting it from equ 4,we get...
4p-9q+1-2(2p+3q-2)=0
4p-9q+1-4p-6q+4=0
-15q+5=0
q=-5/-15
=1/3
∴the value of q is 1/3..
putting the value of q in equ 3 ,we get...
2p+1=2
2p=1
p=1/2
putting the values of p and q in (1/√x=p and 1/√y=q), we get..
1/√x=1/2 and 1/√y=1/3
1/x=1/4 and 1/y=1/3
x=4 and y=9
∴the values of x and y are x=4
y=9
hope my ans helps u buddy..^-^
plzz....make my ans as brainliest .....
here the ans is....
2/√x+ 3/√y =2 equ....1
4/√x +9/√y=-1 equ...2
let 1/√x=p and 1/√y=q
putting this in equ..1 and 2,we get..
2p+3q=2 equ....3
4p-9q= -1 equ...4
multiplying equ 3 by equ 2 and subtracting it from equ 4,we get...
4p-9q+1-2(2p+3q-2)=0
4p-9q+1-4p-6q+4=0
-15q+5=0
q=-5/-15
=1/3
∴the value of q is 1/3..
putting the value of q in equ 3 ,we get...
2p+1=2
2p=1
p=1/2
putting the values of p and q in (1/√x=p and 1/√y=q), we get..
1/√x=1/2 and 1/√y=1/3
1/x=1/4 and 1/y=1/3
x=4 and y=9
∴the values of x and y are x=4
y=9
hope my ans helps u buddy..^-^
plzz....make my ans as brainliest .....
shuzu:
tq ...
Similar questions