Question

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MATHEMATICS WORKBOOK/CLASS
13. A floor 26m by 14m is to be covered by tiles 28cm by 13cm. How many tiles
required to cover the floor?
WER:​

Answer 1

Answer:

Length of floor = 4 metres

Length of floor = 4 metresbreadth of the floor = 3 metres

Length of floor = 4 metresbreadth of the floor = 3 metresArea of the floor = 4m * 3m = 12 sq.m

Length of floor = 4 metresbreadth of the floor = 3 metresArea of the floor = 4m * 3m = 12 sq.mlenght of the tile = 20cm

Length of floor = 4 metresbreadth of the floor = 3 metresArea of the floor = 4m * 3m = 12 sq.mlenght of the tile = 20cmarea of the tile = 20 * 20 = 400cm^2

Length of floor = 4 metresbreadth of the floor = 3 metresArea of the floor = 4m * 3m = 12 sq.mlenght of the tile = 20cmarea of the tile = 20 * 20 = 400cm^212 sq. m = 120000 sq. cm

Length of floor = 4 metresbreadth of the floor = 3 metresArea of the floor = 4m * 3m = 12 sq.mlenght of the tile = 20cmarea of the tile = 20 * 20 = 400cm^212 sq. m = 120000 sq. cmno.of tiles required = 120000/400 = 300 tiles

Length of floor = 4 metresbreadth of the floor = 3 metresArea of the floor = 4m * 3m = 12 sq.mlenght of the tile = 20cmarea of the tile = 20 * 20 = 400cm^212 sq. m = 120000 sq. cmno.of tiles required = 120000/400 = 300 tilestherefore, you require 300 tiles to cover your floor

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