Question

.: S.P.
9: A carpenter sold two tables for 9,900 each. By doing so, he had a gain of 10% on one
per cent.
and a loss of 10% on the other. Find his net gain or loss
feach tahle he 100.​

Answer 1

Answer:

In the first case he gains 10%

In the first case he gains 10%∴ C. P. of the first Table

In the first case he gains 10%∴ C. P. of the first Table=

In the first case he gains 10%∴ C. P. of the first Table= 110

In the first case he gains 10%∴ C. P. of the first Table= 110100×9900

In the first case he gains 10%∴ C. P. of the first Table= 110100×9900

In the first case he gains 10%∴ C. P. of the first Table= 110100×9900 =Rs.9000

In the first case he gains 10%∴ C. P. of the first Table= 110100×9900 =Rs.9000In the second case he loses 10%

In the first case he gains 10%∴ C. P. of the first Table= 110100×9900 =Rs.9000In the second case he loses 10%∴ C. P. of the second Table

In the first case he gains 10%∴ C. P. of the first Table= 110100×9900 =Rs.9000In the second case he loses 10%∴ C. P. of the second Table=

In the first case he gains 10%∴ C. P. of the first Table= 110100×9900 =Rs.9000In the second case he loses 10%∴ C. P. of the second Table= 90

In the first case he gains 10%∴ C. P. of the first Table= 110100×9900 =Rs.9000In the second case he loses 10%∴ C. P. of the second Table= 90100×9900

In the first case he gains 10%∴ C. P. of the first Table= 110100×9900 =Rs.9000In the second case he loses 10%∴ C. P. of the second Table= 90100×9900

In the first case he gains 10%∴ C. P. of the first Table= 110100×9900 =Rs.9000In the second case he loses 10%∴ C. P. of the second Table= 90100×9900 =Rs.11000

In the first case he gains 10%∴ C. P. of the first Table= 110100×9900 =Rs.9000In the second case he loses 10%∴ C. P. of the second Table= 90100×9900 =Rs.11000∴ Total cost of both Tables

In the first case he gains 10%∴ C. P. of the first Table= 110100×9900 =Rs.9000In the second case he loses 10%∴ C. P. of the second Table= 90100×9900 =Rs.11000∴ Total cost of both Tables=9000+11000=Rs.20000

In the first case he gains 10%∴ C. P. of the first Table= 110100×9900 =Rs.9000In the second case he loses 10%∴ C. P. of the second Table= 90100×9900 =Rs.11000∴ Total cost of both Tables=9000+11000=Rs.20000∴ Total S. P. of both Tables

In the first case he gains 10%∴ C. P. of the first Table= 110100×9900 =Rs.9000In the second case he loses 10%∴ C. P. of the second Table= 90100×9900 =Rs.11000∴ Total cost of both Tables=9000+11000=Rs.20000∴ Total S. P. of both Tables=2×9900=Rs.19800

In the first case he gains 10%∴ C. P. of the first Table= 110100×9900 =Rs.9000In the second case he loses 10%∴ C. P. of the second Table= 90100×9900 =Rs.11000∴ Total cost of both Tables=9000+11000=Rs.20000∴ Total S. P. of both Tables=2×9900=Rs.19800∴ Total loss =20000−19800=Rs.200

In the first case he gains 10%∴ C. P. of the first Table= 110100×9900 =Rs.9000In the second case he loses 10%∴ C. P. of the second Table= 90100×9900 =Rs.11000∴ Total cost of both Tables=9000+11000=Rs.20000∴ Total S. P. of both Tables=2×9900=Rs.19800∴ Total loss =20000−19800=Rs.200∴ % of loss =

In the first case he gains 10%∴ C. P. of the first Table= 110100×9900 =Rs.9000In the second case he loses 10%∴ C. P. of the second Table= 90100×9900 =Rs.11000∴ Total cost of both Tables=9000+11000=Rs.20000∴ Total S. P. of both Tables=2×9900=Rs.19800∴ Total loss =20000−19800=Rs.200∴ % of loss = 20000

In the first case he gains 10%∴ C. P. of the first Table= 110100×9900 =Rs.9000In the second case he loses 10%∴ C. P. of the second Table= 90100×9900 =Rs.11000∴ Total cost of both Tables=9000+11000=Rs.20000∴ Total S. P. of both Tables=2×9900=Rs.19800∴ Total loss =20000−19800=Rs.200∴ % of loss = 20000200×100

In the first case he gains 10%∴ C. P. of the first Table= 110100×9900 =Rs.9000In the second case he loses 10%∴ C. P. of the second Table= 90100×9900 =Rs.11000∴ Total cost of both Tables=9000+11000=Rs.20000∴ Total S. P. of both Tables=2×9900=Rs.19800∴ Total loss =20000−19800=Rs.200∴ % of loss = 20000200×100

In the first case he gains 10%∴ C. P. of the first Table= 110100×9900 =Rs.9000In the second case he loses 10%∴ C. P. of the second Table= 90100×9900 =Rs.11000∴ Total cost of both Tables=9000+11000=Rs.20000∴ Total S. P. of both Tables=2×9900=Rs.19800∴ Total loss =20000−19800=Rs.200∴ % of loss = 20000200×100 =1%

In the first case he gains 10%∴ C. P. of the first Table= 110100×9900 =Rs.9000In the second case he loses 10%∴ C. P. of the second Table= 90100×9900 =Rs.11000∴ Total cost of both Tables=9000+11000=Rs.20000∴ Total S. P. of both Tables=2×9900=Rs.19800∴ Total loss =20000−19800=Rs.200∴ % of loss = 20000200×100 =1%