s. Prove that; sin^2+cos^2 =1 .
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Step-by-step explanation:
To prove :- sin^2A + cos^2A = 1
Proof :-
Let ABC be a right angled ∆ , right angled at B and <C = theta
We have ,
sin theta = AB/AC
cos theta = BC/AC
Now , sin^2theta + cos^2theta = (AB/AC)^2 +( BC/AC)^2
= (AB^2+ BC^2)/AC^2
= AC^2/AC^2 {using Pythagoras theorem}
= 1
Hence , proved
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