Question

s radlus.
• A wire is bent in the form of a square of area 1936 cm2. If the same wire is bent to form a
circle, find the radius of the circle and the area enclosed.​

Answer 1

Step-by-step explanation:

$area \: of \: squre \: = {(side)}^{2} \\ 1936 = {(side)}^{2} \\ side \: = 44 \\ perimeter \: of \: square \: \: = side \times 4 \\ = 44 \times 4 \\ = 176 cm\\ perimeter \: of \: square \: = circumference \: of \: circle \\ 176 = 2 \: \pi \: r \\ \frac{176}{2} = \pi \: r \\ 88 = \frac{22}{7} \times r \\ \frac{88 \times 7}{22} = r \\ 28 = r \\ area \: of \: circle \: = \pi \: {r}^{2} \\ = \frac{22}{7} \times 28 \times 28 \\ = 2464 {cm}^{2}$

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Answer 2

Step-by-step explanation:

area of square=1936

(side)²=1936

side=√1936

=44

perimeter of circle=perimeter of square

2πr=4*side

2*22/7*r=4*44

r=7*4*44/2*22

=28cm

area of circle

πr²=22/7*28*28

=88*28

=2464cm²

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thank u