Question

ᴡʜᴇɴ ɪᴛ ɪs ʀᴀɪɴɪɴɢ ᴠᴇʀᴛɪᴄᴀʟʟʏ ᴅᴏᴡɴ,,ᴛᴏ ᴀ ᴍᴀɴ ᴡᴀʟᴋɪɴɢ ᴏɴ ᴛʜᴇ ʀᴏᴀᴅ,ᴛʜᴇ ᴠᴇʟᴏᴄɪᴛʏ ᴏғ ʀᴀɪɴ ᴀᴘᴘᴇᴀʀs ᴛᴏ ʙᴇ 1.5 ᴛɪᴍᴇs ᴛᴏ ʙ ʜɪᴛs ᴠᴇʟᴏᴄɪᴛʏ. ᴀᴛ ᴡʜᴀᴛ ᴀɴɢʟᴇ ᴡɪᴛʜ ᴛʜᴇ ᴠᴇʀᴛɪᴄᴀʟ ʜᴇ ʜᴀs ᴛᴏ ʜᴏʟᴅ ᴛʜᴇ ᴜᴍʙʀᴇʟʟᴀ ᴛᴏ ᴘʀᴏᴛᴇᴄᴛ ʜɪᴍsᴇʟғ ғʀᴏᴍ ʀᴀɪɴ ?

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Answer 1

Answer:

♡HELLO♡

if \: \alpha \: is \: the \: angle \: made \: by \: umbrella \: with \: horizontal \: then \: tan \alpha = vr \div vmifαistheanglemadebyumbrellawithhorizontalthentanα=vr÷vm

IN THE GIVEN PROBLEM,

Vrm =1.5x =3x/2

Vm =x

Vr =?

vrm {}^{2} = vr {}^{2} + vm {}^{2}vrm

2

=vr

2

+vm

2

vr {}^{2} = 9x {}^{2} - 4x {}^{2} \div 4vr

2

=9x

2

−4x

2

÷4

= 5x^2 /4

Vr = root5 x/2

so now, Tan a = Vr/m = root5/2

{\boxed{Angle = tan^-1 ×2/root5}}

Angle=tan

−

1×2/root5

HOPE IT HELPS :)