Question

ᴀ ᴄɪʀᴄᴜʟᴀʀ ᴄᴏɪʟ ᴏғ ᴡɪʀᴇ ᴄᴏɴsɪsᴛɪɴɢ ᴏғ 100 ᴛᴜʀɴs, ᴇᴀᴄʜ ᴏғ ʀᴀᴅɪᴜs 8.0 ᴄᴍ ᴄᴀʀʀɪᴇs ᴀ ᴄᴜʀʀᴇɴᴛ ᴏғ 0.40 ᴀ. ᴡʜᴀᴛ ɪs ᴛʜᴇ ᴍᴀɢɴɪᴛᴜᴅᴇ ᴏғ ᴛʜᴇ ᴍᴀɢɴᴇᴛɪᴄ ғɪᴇʟᴅ ʙ ᴀᴛ ᴛʜᴇ ᴄᴇɴᴛʀᴇ ᴏғ ᴛʜᴇ ᴄᴏɪʟ?​

Answer 1

Qυεѕтìσи-

• ᴀ ᴄɪʀᴄᴜʟᴀʀ ᴄᴏɪʟ ᴏғ ᴡɪʀᴇ ᴄᴏɴsɪsᴛɪɴɢ ᴏғ 100 ᴛᴜʀɴs, ᴇᴀᴄʜ ᴏғ ʀᴀᴅɪᴜs 8.0 ᴄᴍ ᴄᴀʀʀɪᴇs ᴀ ᴄᴜʀʀᴇɴᴛ ᴏғ 0.40 ᴀ. ᴡʜᴀᴛ ɪs ᴛʜᴇ ᴍᴀɢɴɪᴛᴜᴅᴇ ᴏғ ᴛʜᴇ ᴍᴀɢɴᴇᴛɪᴄ ғɪᴇʟᴅ ʙ ᴀᴛ ᴛʜᴇ ᴄᴇɴᴛʀᴇ ᴏғ ᴛʜᴇ ᴄᴏɪʟ?

Sσlυтìσи-

Number of turns on the circular coil, n = 100

Radius of each turn, r = 8.0 cm = 0.08 m

Current flowing in the coil, I = 0.4 A

Magnitude of the magnetic field at the centre of the coil is given by the relation,

| B | = μ0 2πnI / 4π r

Where,

μ0 = Permeability of free space

= 4π × 10^-7 T m A^-1

| B | = 4π x 10-7 x 2π x 100 x 0.4 / 4π x 0.08

= 3.14 x 10^-4 T

Hence, the magnitude of the magnetic field is 3.14 × 10^-4 T.

Explanation:

Relevant answer bhi report kr diya (　`ω´)

Answer 2

Answer:

Number of turns on the circular coil, n = 100

Radius of each turn, r = 8.0 cm = 0.08m

Current flowing in the coil, I = 0.4A

Magnitude of the magnetic field at the centre of the coil is given by the relation,

| B | = μ0 2πnI / 4π r

Where,

μ0 = Permeability of free space

$= 4\pi \times {10}^{ - 7} t \: \: m \: \: {a}^{ - 1}$

$|b| = 4\pi \times {10}^{ - 7} \times 2\pi \times 100 \times 0.4 \div 4\pi \times 0.08$

$= 3.14 \times {10}^{ - 4} t$

Hence the magnitude of magnetic field is

$= 3.14 \times {10}^{ - 4} t$

Hope it's helpful to you bahut jyda ✌️