ᴀɴsᴡᴇʀ ᴋʀᴋᴇ ᴅɪᴋʜᴀᴏ ᴛᴏ ᴊᴀᴀɴᴜ
ᴡɪᴛʜᴏᴜᴛ sᴏʟᴠɪɴɢ ᴛʜᴇ ғᴏʟʟᴏᴡɪɴɢ ǫᴜᴀᴅʀᴀᴛɪᴄ ᴇǫᴜᴀᴛɪᴏɴ, ғɪɴᴅ ᴛʜᴇ ᴠᴀʟᴜᴇ ᴏғ 'ᴍ' ғᴏʀ ᴡʜɪᴄʜ ᴛʜᴇ ɢɪᴠᴇɴ ᴇǫᴜᴀᴛɪᴏɴ ʜᴀs ʀᴇᴀʟ ᴀɴᴅ ᴇǫᴜᴀʟ ʀᴏᴏᴛs.
x² + 2 (m-l) x + (m+5) =0
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Answered by
2
Answer:
b²-4ac=0. when a equation has real and equal roots
so
a=1
b=2(m-l)
c=(m+5)
now
b²-4ac=0
(2(m-l))²-4×1(m+5)=0
(2m-2)²-4m-20=0
4m²+4-8m-4m-20=0
m²+1-2m-m-5=0
m²-3m-4=0
m²-4m+m-4=0
m(m-4)+1(m-4)=0
(m-4)(m+1)=0
so,m=-1,4
hope it helps you follow me
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