Question

ғɪɴᴅ ᴛʜᴇ ᴀʀᴇᴀ ᴏғ ᴀ ʀᴇᴄᴛᴀɴɢʟᴇ ɪғ ɪᴛ's ᴘᴇʀɪᴍᴇᴛᴇʀ ɪs 164ᴄᴍ,ᴡʜᴇʀᴇ ɪᴛ's ʟᴇɴɢᴛʜ ɪs 16ᴄᴍ​

Answer 1

$\huge\boxed{\fcolorbox{black}{pink}{Answer}}</p><p>$

Let the number of boys be 'x'.

So number of boys = x

Number of girls = Number of boys + 52

= x + 52

Total number of students = 1260

A/q Total number of students = 1260

⟹ Number of Boys + Number of Girls = 1260

⟹ x + x + 52 = 1260

⟹ 2x = 1260 - 52

⟹ 2x = 1208

⟹ x = 1208/2

⟹ x = 604

Therefore, the number of boys = 604

So, the number of girls = x + 52

= 604 + 52

= 656

Answer 2

ANSWER✔

$\large\underline\bold{GIVEN,}$

$\sf\dashrightarrow perimeter\:of\:rectangle\:is\:164cm.$

$\sf\dashrightarrow length(L)= 16cm$

$\large\underline\bold{TO\:FIND ,}$

$\sf\dashrightarrow AREA\:OF\:RECTANGLE$

✯ FOMULA IN USE,

$\large{\boxed{\bf{ \star\:\: PERIMETER\:OF\:RECTANGLE:- 2 \times (LENGTH+BREADTH) \:\: \star}}}$

$\large\underline\bold{AREA\:OF\:RECTANGLE\:=LENGTH \times \: BREADTH}$

$\large\underline\bold{SOLUTION,}$

$\sf\dashrightarrow LENGTH(L)=8cm$

$\sf\dashrightarrow BREADTH (B)= ?$

FIRST FINDING THE BREADTH,

THEREFORE,

$\sf\therefore PERIMETER\:OF\:RECTANGLE:- 2 \times (LENGTH+BREADTH)$

$\sf\implies 164=2\times (8+b)$

$\sf\implies \dfrac{164}{2} = 8+b$

$\sf\implies \cancel \dfrac{164}{2} = 8+b$

$\sf\implies 84= 8+b$

$\sf\implies 84-8=b$

$\sf\implies 76cm$

$\large{\boxed{\bf{ \star\:\: breadth= 76cm\:\: \star}}}$

NOW,

$\sf\dashrightarrow LENGTH(L)=8cm$

$\sf\dashrightarrow BREADTH (B)= 76cm$

$\sf\therefore AREA\:OF\:RECTANGLE\:=LENGTH \times \: BREADTH$

$\sf\implies 8 \times 76$

$\sf\implies 608cm^2$

$\large{\boxed{\bf{ \star\:\:area\:of\:rectangle= 608cm^2\:\: \star}}}$

$\large\underline\bold{AREA\:OF\:RECTANGLE= 608cm^2}$

____________________

✯REFER THE DIAGRAM,

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