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Answers
☆Question:
Prove that in a parallelogram, opposite angles are equal.
☆Answer:
Given:A quadrilateral ABCD in which AB=CD and BC=DA.
To prove:ABCD is a parallelogram.
Construction:Join AC.
Proof:
In ∆s ABC and CAD,we have
AC=AC. [Common side]
CB=AD. [Given]
AB=CD. [Given]
So,by SSS criterion of congruence,we obtain
∆ACB≅∆CAD
⇒ ∠CAB=∠ACD [∵Corresponding parts of Congruent triangles are equal] ....(i)
and, ∠ACB=CAD
Now, line AC intersects AB and DC at A and C, such that
∠CAB=∠ACD [from(i)]
i.e., alternate interior angles are equal.
∴AB||BC. ....(ii)
Similarly, line AC intersects BC and AD at C and A, such that
∠ACB=CAD. [from(i)]
i.e., alternate interior angles are equal.
∴BC||AD. ....(iii)
From (ii) and (iii),we have
AB||DC and BC||AD
Hence,ABCD is a parallelogram.
Answer:
Tum hoga pagal inshan kyuki ye sab me ye nhi Karthi aap Faltu bata Kartha ho
ok
Explanation:
And You are also mad OK pagal