Question

ғᴀᴛʜᴇʀ's ᴀɢᴇ ɪs 3 ᴛɪᴍᴇ ᴛʜᴇ sᴜᴍ ᴀɢᴇs oғ ʜɪs ᴛᴡᴏ ᴄʜɪʟᴅʀᴇɴ.ᴀғᴛᴇʀ 5 ʏᴇᴀʀs ʜɪs ᴀɢᴇ ᴡɪʟʟ ʙᴇ ᴛᴡɪᴄᴇ ᴛʜᴇ sᴜᴍ ᴏғ ᴀɢᴇs ᴏғ ᴛᴡᴏ ᴄʜɪʟᴅʀᴇɴ.ғɪɴᴅ ᴛʜᴇ ᴀɢᴇ ᴏғ ғᴀᴛʜᴇʀ.​

Answer 1

Step-by-step explanation:

$\Huge\red{\mathfrak{ Answer }}$

Given

Let's age of two children be x and y

then Father's age = 3(x+y)

After 5 years, father's age will be 3(x+y)+ 5

And that of two children will be x+5+y+5= x+y+10

A/Q

3(x+y)+5= 2(x+y+10)

Let's denote x+y as z then we have

3z+5= 2(z+10)

=> 3z+5= 2z+20

=> 3z-2z= 20-5

=>z = 15

so sum of two children = x+y= 15 years

then father's age will be 3(x+y)= 3(15)= 45 years

hope it helps ✌

Answer 2

$\huge\underline\bold\red{AnswEr}$

Let the age of father =x years

The sum of the age of 2 children =y years

According to the first condition

⇒x=3y.....eq1

After 5 years

⇒ Father's age =x+5

⇒ The sum of ages of his two children =y+10

According to the second condition

⇒x+5=2(y+10)⇒x+5=2y+20

⇒x−2y=15....eq2

Put the value of x from eq1

⇒3y−2y=15⇒y=15

Put y=15 in eq1

⇒x=3×15⇒x=45

Hence, father age =45 years