Math, asked by jaatsahab67, 16 days ago

ᴊɪɴɴɪ ʀᴇsᴘᴇᴄᴛ ᴅᴠᴏɢᴇ ᴏɴɴɪ ᴍɪʟᴜɢɪ
ᴊᴇ ɴᴀ ᴅɪ ᴛᴀ ᴀᴀᴘᴀ ᴋᴇᴅᴀ ᴛᴜʜᴀɴᴜ ᴀᴀᴠᴅᴇ sʀ ᴛᴇ ʙᴀɪᴛʜᴀɴᴀ ᴀᴀ ᴛᴜʜᴀɴᴜ✌​

Answers

Answered by gurjinderk085
5

Answer:

bro mein 50 pnts vala question tuhade lie rakhya c plz Ohnu jaldi gain kr lavo

Answered by llAujlaUstaadll
8

Step-by-step explanation:

Rating of bulb is given as 220 V,100W i.e V

b

=200 V and P

b

=100 W

Thus resistance of bulb R=

P

b

V

b

2

=

100

(200)

2

=400 Ω

Equivalent resistance of 5 bulbs connected in series R

s

=5R=5×400=2000Ω

Supply voltage V

s

=200 V

So, current in the circuit I=

R

s

V

s

=

2000

200

=0.1 A

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