ǫᴜᴇsǫᴜᴇs
A cracker of mass 100g explodes into two pieces of equal mass show that these two pieces of the cracker fly in opposite direction that is v1 =-v2
Answers
Total mass = 100g
Devided into Two pieces of equal mass
━━━━━━━━━━━━━━━━
Need to show:
The two pieces fly in opposite direction with same velocity.
━━━━━━━━━━━━━━━━
Solution:
Let one mass be m1 and other be m2
Total mass be= M= 100g
━━━━━━━━━━
As the two masses are equal so,
m1 = m2 = M/2
⟹ m1 = m2 = 100÷ 2g
⟹{ m1 = m2 = 50g}}m1=m2=50g
━━━━━━━━━━
In a closed system momentum is conserved. Implies \Delta P=0ΔP=0
At the beginning,
P= Mass × Velocity
⟹ P = 100 × 0
⟹\P=0
━━━━━━━━━━━
As momentum is conserved so
Final momentum = Initial momentum
⟹ P= m1v₁ + m2v₂
⟹ 0 = 50 v₁ + 50v₂
⟹(-50 v₂)= 50v₁
Answer:
The question can be solved by using the conservation of momentum.
Therefore,
100*0 = 50v1 + 50v2
v1 = -v2
Hence the negative sign shows that their velocites are in opposite direction.
Total mass = 100g
Devided into Two pieces of equal :
The two pieces fly in opposite direction with same velocity.
Solution:
Let one mass be m1 and other be m2
Total mass be= M= 100g
As the two masses are equal so,
m1 = m2 = M/2
m1 = m2 = 100÷ 2g
{ m1 = m2 = 50g}}m1=m2=50g
In a closed system momentum is conserved. Implies \Delta P=0ΔP=0
At the beginning,
P= Mass × Velocity
P = 100 × 0
P=0
As momentum is conserved so
Final momentum = Initial momentum
P= m1v₁ + m2v₂
0 = 50 v₁ + 50v₂
(-50 v₂)= 50v