s(s-a)tanA/2=s(s-b)tanB/2=s(s-c)tanC/2
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To prove that:
.
L.H.S. =
Using the identity:
=
=
= Δ
M.H.S. =
Using the identity:
=
=
= Δ
R.H.S. =
Using the identity:
=
=
= Δ
∴ L.H.S. = M.H.S. = M.H.S. = Δ
Thus, , proved.
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