Question

ᴀ ᴄɪʀᴄʟᴇ ɪs ᴛᴏᴜᴄʜɪɴɢ ᴛʜᴇ sɪᴅᴇ ʙᴄ ᴏғ ∆ᴀʙᴄ ᴀᴛ ᴘ ᴀɴᴅ ᴛᴏᴜᴄʜɪɴɢ ᴀʙ ᴀɴᴅ ᴀᴄ ᴘʀᴏᴅᴜᴄᴇᴅ ᴀᴛ ǫ ᴀɴᴅ ʀ ʀᴇsᴘᴇᴄᴛɪᴠᴇʟʏ. ᴘʀᴏᴠᴇ ᴛʜᴀᴛ

ᴀǫ= 1÷2(ᴘᴇʀɪᴍᴇᴛᴇʀ ᴏғ ∆ᴀʙᴄ)



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Answer 1

$\huge\bold\red{AnSwer✿᭄}$

Lengths of Δ drawn from an external pt to a circle are equal.

⇒ AQ=AR, BQ=BP, CP=CR$$

Perimeter of ΔABC=AB+BC+CA

=AB+(BP+PC)+(AR−CR)

=(AB+BQ)+PC+(AQ−PC)

=AQ+AQ=2AQ

AQ=½(perimeter of ΔABC).

Answer 2

Answer:

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Step-by-step explanation:

Lengths of Δ drawn from an external pt to a circle are equal.

⇒ AQ=AR, BQ=BP, CP=CR

Perimeter of ΔABC=AB+BC+CA

=AB+(BP+PC)+(AR−CR)

=(AB+BQ)+PC+(AQ−PC)

=AQ+AQ=2AQ

AQ=½(perimeter of ΔABC).