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Explanation:
HEY MATE HERE IS YOUR ANSWER
GIVEN: Bisectors of <pqr and <prs Meet at point A.
TO BE PROVED : <QTR=1/2<QPR
A T.Q.
In∆QTR,∆TRS is an exterior angle
<QTR + <TQR=<TRS
<QTR=<TRS ---<TQR----------(1)
For ∆PQR,< PRS is an external<
<QPR + <PQR =<PRS
<QPR + 2<TQR =2<TRS (As QT and Rt are angle Bisectors
<QPR = 2(<TRS ---<TQR )
<QPR =2<QTR ( By using eqn . 1 )
<QTR = 1/2 <QPR
HENCE PROVED
HOPE IT HELPS YOU
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Answer:
Refer to. the attachment ......⬆⬆⬆
1/2ΔRPS=ΔQtR...
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