Question

ᴛᴡᴏ ʀᴇsɪsᴛᴏʀ ᴏғ ʀᴇsɪsᴛᴀɴᴄᴇ ᴏғ 10 ᴏʜᴍs ᴀɴᴅ 20 ᴏʜᴍs ᴀʀᴇ ᴄᴏɴɴᴇᴄᴛᴇᴅ ɪɴ ᴘᴀʀᴀʟʟᴇʟ. ᴀ ʙᴀᴛᴛᴇʀʏ sᴜᴘᴘʟɪᴇs ᴀ ᴄᴜʀʀᴇɴᴛ ᴏғ 6ᴀ ᴛᴏ ᴛʜᴇ ᴄᴏᴍʙɪɴᴀᴛɪᴏɴ. ᴄᴀʟᴄᴜʟᴀᴛᴇ ᴛʜᴇ ᴄᴜʀʀᴇɴᴛ ɪɴ ᴇᴀᴄʜ ᴏғ ᴛʜᴇ ʀᴇsɪsᴛᴏʀ ᴀɴᴅ ᴘᴏᴡᴇʀ ᴏғ ᴇᴀᴄʜ ʀᴇsɪsᴛᴏʀ​

Answer 1

Answer :-

→ Current in 10 Ω resistor = 4 A

→ Current in 20 Ω resistor = 2 A

→ Power of the 10 Ω resistor = 160 W

→ Power of the 20 Ω resistor = 80 W

Explanation :-

We have :-

→ 1st resistance (R₁) = 10 Ω

→ 2nd resistance (R₂) = 20 Ω

→ Total current (I) = 6 A

______________________________

The current in the 10 Ω resistor is :-

I₁ = (R₂/R₁ + R₂) × I

⇒ I₁ = (20/10 + 20) × 6

⇒ I₁ = 20/30 × 6

⇒ I₁ = 4 A

The current in the 20 Ω resistor :-

I₂ = (R₁/R₁ + R₂) × I

⇒ I₂ = (10/10 + 20) × 6

⇒ I₂ = 10/30 × 6

⇒ I₂ = 2 A

______________________________

Power of 10 Ω resistor :-

P₁ = I²₁ × R₁

⇒ P₁ = (4)² × 10

⇒ P₁ = 16 × 10

⇒ P₁ = 160 W

Power of 20 Ω resistor :-

P₂ = I²₂ × R₂

⇒ P₂ = (2)² × 20

⇒ P₂ = 4 × 20

⇒ P₂ = 80 W

Answer 2

Answer:

❝ᴛʜᴇ ᴄᴏʟᴏʀ ᴠɪᴏʟᴇᴛ ɪɴsᴘɪʀᴇs ᴜɴᴄᴏɴᴅɪᴛɪᴏɴᴀʟ ᴀɴᴅ sᴇʟғʟᴇss ʟᴏᴠᴇ, ɪs ᴇɴᴄᴏᴜʀᴀɢɪɴɢ, sᴇɴsɪᴛɪᴠᴇ ᴀɴᴅ ᴄᴏᴍᴘᴀssɪᴏɴᴀᴛᴇ. ᴠɪᴏʟᴇᴛ ᴇɴᴄᴏᴜʀᴀɢᴇs ᴄʀᴇᴀᴛɪᴠᴇ ᴘᴜʀsᴜɪᴛs ᴀɴᴅ sᴇᴇᴋs ɪɴsᴘɪʀᴀᴛɪᴏɴ ᴀɴᴅ ᴏʀɪɢɪɴᴀʟɪᴛʏ. ɪᴛ ɪs ᴜɴɪǫᴜᴇ, ɪɴᴅɪᴠɪᴅᴜᴀʟ ᴀɴᴅ ɪɴᴅᴇᴘᴇɴᴅᴇɴᴛ. ᴠɪᴏʟᴇᴛ ᴜsᴇs ɪᴛs ʙᴇᴛᴛᴇʀ ᴊᴜᴅɢᴍᴇɴᴛ ᴛᴏ ᴅᴏ ɢᴏᴏᴅ ғᴏʀ ᴏᴛʜᴇʀs, ᴄᴏᴍʙɪɴɪɴɢ ᴡɪsᴅᴏᴍ ᴀɴᴅ ᴘᴏᴡᴇʀ ᴡɪᴛʜ sᴇɴsɪᴛɪᴠɪᴛʏ ᴀɴᴅ ʜᴜᴍɪʟɪᴛʏ.❞