Question

ᴛᴡᴏ ʀᴇsɪsᴛᴏʀ ᴏғ ʀᴇsɪsᴛᴀɴᴄᴇ ᴏғ 10 ᴏʜᴍs ᴀɴᴅ 20 ᴏʜᴍs ᴀʀᴇ ᴄᴏɴɴᴇᴄᴛᴇᴅ ɪɴ ᴘᴀʀᴀʟʟᴇʟ. ᴀ ʙᴀᴛᴛᴇʀʏ sᴜᴘᴘʟɪᴇs ᴀ ᴄᴜʀʀᴇɴᴛ ᴏғ 6ᴀ ᴛᴏ ᴛʜᴇ ᴄᴏᴍʙɪɴᴀᴛɪᴏɴ. ᴄᴀʟᴄᴜʟᴀᴛᴇ ᴛʜᴇ ᴄᴜʀʀᴇɴᴛ ɪɴ ᴇᴀᴄʜ ᴏғ ᴛʜᴇ ʀᴇsɪsᴛᴏʀ ᴀɴᴅ ᴘᴏᴡᴇʀ ᴏғ ᴇᴀᴄʜ ʀᴇsɪsᴛᴏʀ​

Answer 1

Answer :-

→ Current in 10 Ω resistor = 4 A

→ Current in 20 Ω resistor = 2 A

→ Power of the 10 Ω resistor = 160 W

→ Power of the 20 Ω resistor = 80 W

Explanation :-

We have :-

→ 1st resistance (R₁) = 10 Ω

→ 2nd resistance (R₂) = 20 Ω

→ Total current (I) = 6 A

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The current in the 10 Ω resistor is :-

I₁ = (R₂/R₁ + R₂) × I

⇒ I₁ = (20/10 + 20) × 6

⇒ I₁ = 20/30 × 6

⇒ I₁ = 4 A

The current in the 20 Ω resistor :-

I₂ = (R₁/R₁ + R₂) × I

⇒ I₂ = (10/10 + 20) × 6

⇒ I₂ = 10/30 × 6

⇒ I₂ = 2 A

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Power of 10 Ω resistor :-

P₁ = I²₁ × R₁

⇒ P₁ = (4)² × 10

⇒ P₁ = 16 × 10

⇒ P₁ = 160 W

Power of 20 Ω resistor :-

P₂ = I²₂ × R₂

⇒ P₂ = (2)² × 20

⇒ P₂ = 4 × 20

⇒ P₂ = 80 W

Answer 2

CURRENT OF 6aTO THE COMBINATION CALCULATED THE CURRENT TN EACH OF THE RESISTOR AND POWER OF EACH RESISTER