ᴘʟᴇᴀsᴇ ᴍᴇɴᴛɪᴏɴ ғᴜʟʟ sᴏʟᴜᴛɪᴏɴ ғᴏʀ ᴀʟʟ ǫᴜᴇsᴛɪᴏɴs......
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In triangles RPQ and RTS, we have
∠RPQ=∠RTS [Given]
∠PRQ=∠TRS [Each equal to R]
Therefore, by AA-criterion of similarity, we have
△RPQ∼△RTS. [Hence proved]
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