Question

ᴀ ғʟᴏᴏʀɪɴɢ ᴛɪʟᴇ ɪɴ ᴛʜᴇ sʜᴀᴘᴇ ᴏғ ᴀ ʀʜᴏᴍʙᴜs
ʜᴀs ᴅɪᴀɢᴏɴᴀʟs ᴏғ ʟᴇɴɢᴛʜ 60 ᴄᴍ ᴀɴᴅ 80
ᴄᴍ, ʜᴏᴡ ᴍᴀɴʏ sᴜᴄʜ ᴛɪʟᴇs ᴡɪʟʟ ʙᴇ ʀᴇǫᴜɪʀᴇᴅ
ᴛᴏ ᴄᴏᴠᴇʀ ᴀ ғʟᴏᴏʀ ᴏғ ᴀʀᴇᴀ 360 ᴍº?
​

Answer 1

Answer:

ur answer is

Explanation:

the area is 4800 sq cm..

hope it helps you

Answer 2

Answer:

⚘ Question :

➳ A flooring tile in the shape of a rhombus has diagonals of length 60 cm and 80 cm, how many such tiles will be required to cover a floor of area 360 m²?

$\begin{gathered}\end{gathered}$

⚘ Solution :

$\begin{gathered}{\textsf{\textbf{\underline{\underline{Given :}}}}}\end{gathered}$

• ➳ A flooring tile in the shape of a rhombus has diagonals of length 60 cm and 80 cm

$\begin{gathered}\end{gathered}$

$\begin{gathered}{\textsf{\textbf{\underline{\underline{To Find :}}}}}\end{gathered}$

• ➳ How many such tiles will be required to cover a floor of area 360 m²

$\begin{gathered}\end{gathered}$

$\begin{gathered}{\textsf{\textbf{\underline{\underline{Using Formula :}}}}}\end{gathered}$

$\dag{\underline{\boxed{\sf{Area \: of \: Rhombus = \dfrac{1}{2} \times (D_1) \times (D_2)}}}}$

$\begin{gathered}\end{gathered}$

$\begin{gathered}{\textsf{\textbf{\underline{\underline{Solution :}}}}}\end{gathered}$

$\red\bigstar$ Firstly converting the lenght of diagonals to m.

$: \implies{\sf{1 \: cm = \dfrac{1}{100} \: m}}$

$: \implies{\sf{60\: cm = {\cancel\dfrac{60}{100}} = \dfrac{6}{10} \: m }}$

$: \implies{\sf{80\: cm = {\cancel\dfrac{80}{100}} = \dfrac{8}{10} \: m }}$

∴ The lenght of diagonal are Rhombus is 6/10 m and 8/10 m..

$\begin{gathered}\end{gathered}$

$\red\bigstar$ Now,Calculating the area of rhombus.

${: \longmapsto{\sf{Area \: of \: Rhombus = \dfrac{1}{2} \times (D_1) \times (D_2)}}}$

• Substuting the values

${: \longmapsto{\sf{Area \: of \: Rhombus = \dfrac{1}{2} \times \dfrac{6}{10} \times \dfrac{8}{10} }}}$

${: \longmapsto{\sf{Area \: of \: Rhombus = \dfrac{1}{2} \times 0.6\times 0.8 }}}$

${: \longmapsto{\sf{Area \: of \: Rhombus = \dfrac{1 \times 0.6 \times 0.8}{2}}}}$

${: \longmapsto{\sf{Area \: of \: Rhombus = \dfrac{0.48}{2}}}}$

${: \longmapsto{\sf{Area \: of \: Rhombus = \cancel{\dfrac{0.48}{2}}}}}$

${: \longmapsto{\sf{Area \: of \: Rhombus = 0.24 \: {m}^{2}}}}$

${\bigstar\underline{\boxed{\sf{\blue{Area \: of \: Rhombus} = \purple{0.24 \: {m}^{2}}}}}}$

∴ Area of one tile is 0.24 m

$\begin{gathered}\end{gathered}$

$\red\bigstar$ Now,Calculating the number of tiles will be required to cover a floor of area 360 m².

${: \implies{\sf{Number \: of \: Tiles = \dfrac{Area \: of \: floor }{Area \: of \: one \: tile}}}}$

• Substuting the values

${: \implies{\sf{Number \: of \: Tiles = \dfrac{360}{0.24}}}}$

${: \implies{\sf{Number \: of \: Tiles = \dfrac{360 \times 100}{0.24 \times 100}}}}$

${: \implies{\sf{Number \: of \: Tiles = \dfrac{36000}{24}}}}$

${: \implies{\sf{Number \: of \: Tiles = \cancel{\dfrac{36000}{24}}}}}$

${: \implies{\sf{Number \: of \: Tiles = 1500 \: Tiles}}}$

$\bigstar{\underline{\boxed{\sf{\blue{Number \: of \: Tiles}= \purple{1500 \: Tiles}}}}}$

∴ 1500 tile will be required to cover a floor of area 360 m²..

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