Question

ᴀ ᴠᴏʟᴛᴍᴇᴛᴇʀ ʜᴀᴅ ᴅɪᴠɪsɪᴏɴ ʙᴇᴛᴡᴇᴇɴ ᴛᴏ . ᴠᴏʟᴛs. ғɪɴᴅ ɪᴛ's ʟᴇᴀsᴛ ᴄᴏᴜɴᴛ. ɪғ ᴛʜᴇ ᴠᴏʟᴛ ᴍᴇᴛᴇʀ ᴘᴏɪɴᴛs ᴛʜᴇ ᴠᴀʟᴜᴇ ᴏғ . ᴠᴏʟᴛ ᴀɴᴅ ᴄᴏɴɴᴇᴄᴛᴇᴅ ᴀᴄʀᴏss ᴀ ʀᴇsɪsᴛᴏʀ ᴏғ ᴏʜᴍ. ғɪɴᴅ ᴛʜᴇ ᴄᴜʀʀᴇɴᴛ ғʟᴏᴡɪɴɢ ɪɴ ᴄɪʀᴄᴜɪᴛ.​

Answer 1

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step-by-step explanation:

Formula to find least count:-

Least Count = $\frac{Difference\:between\:two\:consecutive\:readings}{Number\:of\:divisions}$

Here,

Difference between two consecutive readings is

1.5 - 0 = 1.5

Number of divisions = 10

Least Count = 0.15

now,

For the second part of the question,

we would be using the concept of Ohm's Law:-

V = IR

Here, V = 1.8 V

          R = 100

now,

Substituting the values:-

=> 1.8 = I(100)

=> I = 18/1009

=> I = 0.018 A

So,

the Least Count of Voltmeter is 0.15V

and

the current flowing through the circuit is 0.018 A .

Answer 2

step-by-step explanation:

Formula to find least count:-

Least Count = \frac{Difference\:between\:two\:consecutive\:readings}{Number\:of\:divisions}NumberofdivisionsDifferencebetweentwoconsecutivereadings

Here,

Difference between two consecutive readings is

1.5 - 0 = 1.5

Number of divisions = 10

Least Count = 0.15

now,

For the second part of the question,

we would be using the concept of Ohm's Law:-

V = IR

Here, V = 1.8 V

          R = 100

now,

Substituting the values:-

=> 1.8 = I(100)

=> I = 18/1009

=> I = 0.018 A

So,

the Least Count of Voltmeter is 0.15V

and

the current flowing through the circuit is 0.018 A .