ǫᴜᴇsᴛɪᴏɴ ( ᴊᴇᴇ ) ❤ :-
sᴏʟᴠᴇ ᴛʜᴇ ǫᴜᴇsᴛɪᴏɴ ᴏғ ᴀᴛᴛᴀᴄʜᴍᴇɴᴛ ^_^ ......
⍟ ғᴜʟʟ ᴇxᴘʟᴀɴᴀᴛɪᴏɴ ɴᴇᴇᴅᴇᴅ ⍟
ᴛʜᴀɴᴋs :)
ᴀʟʟ ᴛʜᴇ ʙᴇsᴛ ❤ .
Attachments:
Answers
Answered by
27
(B) 3 : 3 : 2
Explanation :-
Case (I) :-
Gravitational force ( Non impulsive)
- I = 0 ( Here, I is Impulse)
- Δp = 2m(v) - mu = 0 ( Here, Δp is change in momentum)
=> 2mv = mu
Case (II) :-
Spring force ( Non impulsive)
- I = 0 ( Here, I is Impulse)
- Δp = 2m(v) - mu = 0 ( Here, Δp is change in momentum)
=> 2mv = mu
From eqn. (1) & (2),
Case (III) :-
- I ≠ 0 (Here, Impulse ≠ 0)
- Δp ≠ 0 (Here, Change in momentum ≠ 0)
=> Δp = 2m(v) - mu = -I
=> I = mv - 0 = mv
=> I = mv.
=> 2mv - mu = -(mv) ( °.° I = mv)
=> 2mv + mv = mu
=> 3mv = mu
From eqn. (1) , (2) & (3),
BloomingBud:
great explanation
Similar questions