Math, asked by trupthi8, 5 hours ago

ɴᴏ sᴘᴀᴍs !

ᴇxᴘʟᴀɴᴀᴛɪᴏɴ ɴᴇᴇᴅᴇᴅ !​

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Answers

Answered by NSR3880
1

Step-by-step explanation:

{a}^{b} = \ {2}^{30} \\{a}^{a} \:  =   \:  {2}^{2}  \:   \\  {b}^{a} =  {30}^{2} \\   {b}^{b}  =  {30}^{30}

(i)

 {( {2}^{30}  +  {30}^{2} )}^{ - 1}  \\  = ( \frac{1}{ {2}^{30}} \:  +  \frac{1}{ {30}^{2} } ) \\

(ii)

 ( {2}^{2}  +  {30}^{30} )^{ - 1}  \\ (  \frac{1}{ {2}^{2} }  +  \frac{1}{ {30}^{30} })  \\

Hope it helps you out

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