Question

S[sin (log x) + cos (log x)] dx =
a) x cos (log x) + c b) sin (log x)+c c) cos (log x)+c
d) x sin (log x) + c
Ti​

Answer 1

Answer:

[sin(logx)+cos(logx)]dx

=∫sin(logx)dx+∫cos(logx)dx

Integrating by parts,

=xsin(logx)−∫cos(logx)dx+∫cos(logx)dx

=xsin(logx)+c.xsin(logx)+c

hope it will help you

correct answer is (c)