Question

ɪғ ᴀ ᴘʟᴀɴᴛ ɪs ᴄʀᴏssᴇᴅ ᴀɴᴅ ᴘʀᴏᴅᴜᴄᴇᴅ ғɪғᴛʏ ᴛᴀʟʟ ᴀɴᴅ sᴇᴠᴇɴᴛᴇᴇɴ ᴅᴡᴀʀғ . ᴡʜᴀᴛ ᴄᴏᴜʟᴅ ʙᴇ ᴛʜᴇ ɢᴇɴᴏᴛʏᴘᴇ ɪɴ ғ1 ɢᴇɴᴇʀᴀᴛɪᴏɴ....
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ᴄʟᴀss x
ᴄʜᴀᴘ - ʜᴇʀɪᴅɪᴛʏ ᴀɴᴅ ᴇᴠᴏʟᴜᴛɪᴏɴ...
sᴜʙ - ʙɪᴏʟᴏɢʏ​

Answer 1

Explanation:

A cross between pure breeding tall (TT) and dwarf (tt) plants produce all tall (Tt) plants in F1 progeny. These heterozygous tall plants produce 50% gametes with "T" allele and 50% with "t" allele. Random fusion of these gametes from two heterozygous tall plants gives tall and dwarf plants in 3:1 ratio. out of 3/4 tall plants; 1/4 are homozygous tall (TT) and 2/4 are heterozygous tall (Tt). This makes the genotypic ratio for F2 generation as 1 homozygous tall (TT): 2 heterozygous tall (Tt): 1 homozygous dwarf (tt).

Answer 2

$\huge\mathfrak{Answer:}$

➡️The ratio of plants crossed and produced = 50 and 17 respectively

➡️50 : 17

➡️3 : 1 ( nearly)

➡️So this type of ratio we can get in

Tt × Tt ..............F1

TT, Tt, Tt, tt .....F2

3 : 1 ( TALL : DWARF )

➡️Hence the Genotype in F1 generation is Tt and Tt