Question

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Starting from a stationary position, Rahul Paddles his bicycle to attain a velocity of 6m/s in 30s. Then he applies brakes such that the velocity of bicycle comes down to 4m/s in the next 5s. Calculate the acceleration of the bicycle in both the cases. ​

Answer 1

Answer :-

1st case :-

Given :-

• Initial velocity = 0 ( starting from stationary )
• Final velocity = 6 m/s
• Time = 30 seconds

To Find :-

• Acceleration

Solution :-

We know that,

→ v = u + at

Substituting the value in formula :-

→ 6 = 0 + a × 30

→ 6 = 30a

→ a = 6 / 30

→ a = 1 / 5

→ a = 0.2

Acceleration = 0.2 m/s²

2nd case :-

Given :-

• Initial velocity = 6 m/s
• Final velocity = 4 m/s
• Time = 5 seconds

To Find :-

• Acceleration

Solution :-

We know that,

→ v = u + at

Substituting the value in formula :-

→ 4 = 6 + 5a

→ -2 = 5a

→ a = -2/5

→ a = -0.4

Acceleration = -0.4 m/s²

Answer 2

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Starting from a stationary position,

Rahul paddles his bicycle to attain a velocity of

6 ms−1 in 30sec. ...

⇒a=630=0.2ms−2.

So in the first case his acceleration is 0.2ms−2 .

Now in the second case he applies brakes such that the velocity of the bicycle comes down to 4m/s in the next 5s.