Question

s= t^2 + 5t + 3
then find ds/dt

Answer 1

hey....
ds/dt=2t+5
hope its help u..

Answer 2

Answer:

Value of

$\frac{ds}{dt}$is (2t+5)

Explanation:

Given,

$s = {t}^{2} + 5t + 3$

Here we want to find value of $\frac{ds}{dt}$

We are differentiating s with respect to t.

$\frac{ds}{dt} = \frac{d}{dt} ( {t}^{2}) + \frac{d}{dt} (5t) + \frac{d}{dt} (3) \\ = 2t + 5 + 0 \\ = 2t + 5$

Required value of $\frac{ds}{dt}$is 2t+5.

Here applied formula,

$\frac{d}{dx} {x}^{n} = n {x}^{n - 1}$

This is a problem of Derivative.

Some important Derivatives formulas,

$1. \frac{d}{dx} ( \sin(x) ) = \cos(x ) \\ 2. \frac{d}{dx} ( \cos(x) ) = - \sin(x) \\ 3. \frac{d}{dx} ( \tan(x) ) = {sec}^{2} x \\ 4. \frac{d}{dx} ( \cot(x) ) = - {cosec}^{2} x \\ 5. \frac{d}{dx} ( \sec(x) ) = \sec(x) \tan(x) \\ 6. \frac{d}{dx} (cosec(x)) = - cosecxcotx$