Question

S-t = 3 and s/3 + t/2 =6 by substitute method

Answer 1

given s-t =3 ...eq1
s/3+t/2=6
2s+3t = 36 ...eq 2
from eq no 1 .
s= 3+t
put the value of s in eq no. 2
6+ 2t+3t=36
5t=30
t= 6
again put the value of t in eq 1
s= 3+6
s=9
I hope it will help you

Answer 2

Answer :-

s - t = 3

s = 3 + t---(1)

s/3 + t/2 = 6

∴ 2s + 3t/6 = 6

∴ 2s + 3t = 36 ---(2)

From equation 1, s = 3 + t in equation 2 we get

2s + 3t = 36

2(3 + t) + 3t = 36

6 + 2t + 3t = 36

5t = 30

∴ t = 6

Now, s - t = 3

s - 6 = 3

∴ s = 9

The required solution is s = 9 and t = 6