Question

s-t=3( eqn1 )
S/3+1/2=6( eqn2 )
Solve this equation by substitution method.​

Answer 1

Answer:

$\huge\underline{ \underline{ \red {your \: \: \: answer}}}$

Step-by-step explanation:

$\small\underline{ \underline{ \purple{using \: substitution \: method}}} \\ \\ \bf\red{ \mapsto:s - t = 3 - - - - - - - (1) } \\ \\ \bf\red{ \implies: s = t + 3 - - - - - (2)} \\ \\ \bf\red{ \implies: \frac{s}{3} + \frac{1}{2} = 6 - - - - - (3) } \\ \\ \bf\red{ \implies: \frac{2s + 3}{6} = 6} \\ \\ \bf\red{ \implies: 2s + 3 = 36} \\ \\ \bf\red{ \implies: 2s = 33} \\ \\ \bf\red{ \implies: s = \frac{33}{2} } \\ \\ \bf\green{value \: of \: s \: put \: in \: (2)} \\ \\ \bf\pink{ \mapsto: \frac{33}{2} = 3 + t} \\ \\ \bf\pink{ \mapsto:t = \frac{33}{2} - 3 } \\ \\ \bf\pink{ \mapsto: \frac{33 - 6}{2} = t} \\ \\ \bf\pink{ \mapsto:t = \frac{27}{2} }$

$\large\boxed{ \fcolorbox{violet}{yellow}{hope \: it \: help \: you}}$