Math, asked by sandhya1051, 9 months ago

s-t=3
s/3+t/2=6
by substitution method​

Answers

Answered by rukumanikumaran
11

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Answered by homework21
2

s-t=3

s=t+3 -eq (1)

s/3+t/2=6 - eq(2)

remove LCM of eq(2)

2s/6+3t/6=6

2s+3t=36 -(3)

add the value of s in eq(3)

2(t+3)+3t=36

2t+6+3t=36

5t=36-6

5t=30

t=30/5

t=6

put the value t in eq(1)

s=6+3

s=9

so, s=9 and t =6

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