s-t=3
s/3+t/2=6
by substitution method
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s-t=3
s=t+3 -eq (1)
s/3+t/2=6 - eq(2)
remove LCM of eq(2)
2s/6+3t/6=6
2s+3t=36 -(3)
add the value of s in eq(3)
2(t+3)+3t=36
2t+6+3t=36
5t=36-6
5t=30
t=30/5
t=6
put the value t in eq(1)
s=6+3
s=9
so, s=9 and t =6
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