Question

S-t=3,s/3+t/2=6 Solve leaniar equation By using substitution method

Answer 1

Hi there!

s-t =3 -----(1)
s/3 + t/2 = 6 ----(2)
Therefore the first equation is easy, so we convert it into this form:-
s-t = 3
s = 3 +t -----(3)

Now substituting equation (3) in (2)
3+t /3 + t/2 =6

Now we take the LCM of their denominators..except for the RHS..

2×{3+t/3} + 3×{t/2} = 6

6+2t+3t the whole divided by 6 = 6
6+2t+3t = 6×6
2t+3t = 36
5t = 36-6=30
t = 30/5
t =6 -----(4)

Now substitute (4) in (3)
s = 3+6
s = 9

Hope it helps you..
Thank you..

Answer 2

Answer:

Step-by-step explanation:

Given :-

s – t = 3              

s/3 + t/2 = 6

Solution :-

⇒ s – t = 3 ... (i)                  

⇒ s/3 + t/2 = 6 ... (ii)                  

From equation (i), we get s = t + 3                  

Putting this value in equation (ii), we get                  

⇒ t + 3/3 + t/2 = 6                  

⇒ 2t + 6 + 3t = 36                  

⇒ 5t = 30                  

⇒ t = 30/5

⇒ t = 6 ... (iv)                  

Putting in equation (iii), we get                  

⇒ s = 9            

   

Hence, s = 9, t = 6