Question

S-t=7 , S*t=9 then what is s^2+t^2

Answer 1

Step-by-step explanation:

GIVEN

S-t = 7

squaring on both sides,

${(s - t)}^{2} = {7}^{2}$

${s}^{2} + {t}^{2} - 2st = 49$

${s}^{2} + {t}^{2} = 49 + 2st$

but given that s×t = 9

${s}^{2} + {t}^{2} = 49 + 2(9)$

${s}^{2} + {t}^{2} = 49 + 18$

${s}^{2} + {t}^{2} = 67$

HOPE IT HELPS.............

PLEASE MARK AS BRAINLIEST...

Answer 2

Answer:

sT t. = 9 + 9. 6. = 3 m>s. Ans. a t=6 = 2 m>s2. Ans. Ans: vavg = 0. (vsp)avg = 3 ... defined by s = (t3 - 6t2 - 15t + 7) ft, where t is in seconds.

I guess this will help you