S, t and u can complete a work in 40, 48 and 60 days respectively. they received rs 10800 to complete the work. they begin the work together but t left 2 days before the completion of the work and u left 5 days before the completion of the work. s has completed the remaining work alone. what is the share of s (in rs) from total money?
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According to question
Work done by s in one day = 1/s = 40
Similarly
1/t = 48
and 1/u = 60
Thus work done by them in one day
1/t + 1/s + 1/u = 40 + 48 + 60
Thus 1/s + 1/t + 1/u = 148
We have to find out
1/s + 1/t-2 + 1/u -5 = 1
So putting the value
148 - 1/t - 1/u + 1/t-2 + 1/u-5 = 1
Work done by s in one day = 1/s = 40
Similarly
1/t = 48
and 1/u = 60
Thus work done by them in one day
1/t + 1/s + 1/u = 40 + 48 + 60
Thus 1/s + 1/t + 1/u = 148
We have to find out
1/s + 1/t-2 + 1/u -5 = 1
So putting the value
148 - 1/t - 1/u + 1/t-2 + 1/u-5 = 1
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