Question

s t and u can complete a work in 40 48 and 60 days respectively. they received rs.10800 to complete the work.they begin the work together but t left 2 days before the completion of work and u left 5 days before the completion of work.s has completed the ramaining work alone. what is the share of s from the total money?

Answer 1

total work=lcm of 40,48,60=240
S 1 days work=240/40=6
T 1 day work=240/48=5
U 1 days work=240/60=4
(S+T+U) 1 day work=6+5+4=15
let x days be the time to complete the work
working days of S =x
working days of T=x-2 days
working days of U=x-5 days
now 6x+5(x-2)+4(x-5)=240
6x+5x-10+4x-20=240
15x-30=240
15x=270
x=270/15=18 days

Answer 2

Answer:

4,860 Rupees

Step-by-step explanation:

suppose s did the work for the x days

then T will do the work for (x-2) days

and U will for (x-5) days now

(x/40)+{(x-2)/48}+{(x-5)/60}=1

6x+5x-10+4x-20=240

i.e. x=18 days means the s did the work for 18 days

T 18-2 i.e. 16 days and U did for 18-5 = 13 days

Now Remuneration for S

{18 (work done for days)/40 (capacity)}*10800

=4,860 Rupees

same for T (16/48)*10800

=3600 Rupees

same for U (13/60)*10800

=1940 Rupees