Question

S-t graph of two particles A and B are shown in fig. then find ratio of velocity of A to velocity of B.
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Answer 1

Given that,

S-t graph of two particles A and B.

Suppose, The displacement time graph for two particles A and B are straight lines inclined at angles of 30° and 60° with the time axis. The ratio of velocities of A to velocity of B

We know that,

Velocity :

The velocity of the particle is rate of change of position of the particle.

$v=\dfrac{dx}{dt}$

$v = \text{slope of x-t graph}$

We need to calculate the ratio of velocity of A to velocity of B

Using formula of velocity for A and B

$\dfrac{v_{A}}{v_{B}}=\dfrac{slope\ A}{slpoe\ B}$

$\dfrac{v_{A}}{v_{B}}=\dfrac{\tan 30^{\circ}}{\tan 60^{\circ}}$

$\dfrac{v_{A}}{v_{B}}=\dfrac{1}{\sqrt{3}\times\sqrt{3}}$

$\dfrac{v_{A}}{v_{B}}=\dfrac{1}{3}$

Hence, The ratio of velocity of A to velocity of B is 1:3.

Answer 2

Explanation:

So ratio of the given graph is 1:3