s. The polynomial, f(x) = x4 – 2x2 + 3x2 - ax + b when divided by (x - 1) and (x + 1) leaves the
remainders 5 and 19 respectively. Find the values of a and b. Hence, find the remainder
when f(x) is divided by (x - 2).
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QUESTION - - -
The polynomial, f(x) = x4 – 2x2 + 3x2 - ax + b when divided by (x - 1) and (x + 1) leaves theremainders 5 and 19 respectively. Find the values of a and b.
ANSWER - - -
The remainder when p is divided by x−1 is is 6 , therefore (remainder theorem)
p(1)=6 .
The other condition, can be written
p(−1)=14 .
These equations are written in terms of a and b as
1−2+3−a+b=6
1+2+3+a+b=14 .
or
−a+b=4
a+b=8 ,
and hence
a=2
b=6 .
The remainder when p is divided by x−2 is (remainder theorem again)
p(2)=16−16+12−4+6=14 .
Therefore, the remainder is 14.
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