Question

s the simple interest on a certain sum for 3 years at 8% per annum is₹ 96 more than the simple interest on the same sum for 2 years at 9% per annum find the sum

Answer 1

let the sum=P
S.I. = P×R×T/100
so acc. to que.
(P×8×3)/100= (P×9×2)/100 + 96
by transpose
P×(24-18)/100=96
p×6=9600
p=9600/6
P=1600rs

Answer 2

$\huge\mathfrak\red{Question:}$

The simple interest on a certain sum for 3 years at 8% per annum is Rs. 96 more than the simple interest on the same sum for 2 years at 9% per annum. Find the sum.

$\huge\mathfrak\green{Solution:}$

Let the required sum be Rs. x. Then,

SI on Rs. x at 8% p.a. for 3 years

$= rs.( \frac{x \times 8 \times 3}{100} ) = rs .\:\frac{6x}{25}$

SI on Rs. x at 9% p.a. for 2 years

$rs.( \frac{x \times 9 \times 2}{100} ) = rs. \frac{9x}{50}$

Hence,

$\frac{6x}{25} - \frac{9x}{50} = 96$

$(12x - 9x) = 96 \times 50$

$3x = 4800$

$x = \frac{4800}{3}$

$x = 1600$

Hence, the required sum is Rs. 1600.