Question

s. The velocity of car increases unifoamly
f from 5 ms
to loms-l
lomst, when it travel
som Find acceleration of car
​

Answer 1

Explanation:

u=5m/s

v=10m/s

s=50m

v²=u²+2as

10²=5²+2×a×50

100=25+100a

75=100a

a=0.75m/s²

hope it helps.....

Answer 2

Correct Question :

➥ The velocity of car increases uniformly from 5 m/s to 10 m/s when it travel 50 m Find acceleration of car.

Answer :

➥ The Acceleration of a car = 0.75 m/s²

Given :

➤ Intial velocity of a car (u) = 5 m/s

➤ Final velocity of a car (v) = 10 m/s

➤ Distance travelled by a car (s) = 50 m

To Find :

➤ Acceleration of a car (a) = ?

Solution :

In the above question given that Intial velocity is m/s, final velocity is 10 m/s and distance covered by car is 50 m. So,

From third equation of motion

$\tt{:\implies {v}^{2} = {u}^{2} + 2as }$

$\tt{:\implies {10}^{2} = {5}^{2} + 2 \times a \times 50 }$

$\tt{:\implies 100 = 25 + 2a \times 50}$

$\tt{:\implies 100 = 25 + 100a}$

$\tt{:\implies 100 - 25 = 100a}$

$\tt{:\implies 75 = 100a}$

$\tt{:\implies \cancel{ \dfrac{75}{100}} = a }$

$\bf{:\implies \underline{ \: \: \underline{ \purple{ \: \: a = 0.75 \: m/s^2 \: \: }} \: \: }}$

Hence, the acceleration of a car is 0.75 m/s².

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Some related equations :

⪼ s = ut + ½ at²

⪼ v = u + at

⪼ v² = u² + 2as