s=ut+1/2at^2 prove it
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Answered by
2
Hey mate....
Here is your answer
If the initial velocity is u...
Final velocity as v...
Time duration as t...
And uniform acceleration as a
Average velocity=(u+v)/2.....1
But by definition, average velocity=total distance travelled/ total time taken. i.e.s/ut......2
From comparing 1 and 2 we get,
(u+v)/2=s/t
s=1/2(u+v)t......3
also we have....v=u+at
So, by substituting the value of v in 3 we get...
s=ut+1/2at^2
Here is your answer
If the initial velocity is u...
Final velocity as v...
Time duration as t...
And uniform acceleration as a
Average velocity=(u+v)/2.....1
But by definition, average velocity=total distance travelled/ total time taken. i.e.s/ut......2
From comparing 1 and 2 we get,
(u+v)/2=s/t
s=1/2(u+v)t......3
also we have....v=u+at
So, by substituting the value of v in 3 we get...
s=ut+1/2at^2
deep1032kir:
I have 1 suggestion
Answered by
4
As we know that area under V-T graph is displacement and area in figure is formed by triangle and rectangle
Area under graph = Area of rectangle + Area of triangle
s = ( l × b ) + ( 1 / 2 × b × h )
s = ( t × u ) + [ 1 / 2 × t × ( v - u ) ]
s = ut + 1 / 2 × t × at [ :. v - u = at ]
Have great future ahead!
जय हिन्द!
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