S=ut+1/2at solve dimensionally
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hey mate✌✌✌
here is your answer ✍✍✍✍
derivation of s = ut +1/2at^2
here,
given
AO=u
BC=v
BD=at
OC=t
area of trapezium AOCB s =area of ∆ABD+area of rectangle AOCD
s=1/2(AD×BD)+0A×0C
s=1/2(at×t)+ut
s=1/2at^2+ut
s=ut+1/2at^2
...........................hence derived
hope it helps u ☺☺☺
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