Question

S ut 1 2at2 this equation is dimensionally correct prove that

Answer 1

Distance travelled = Area under the line 
= ut + ½ (v-u)t
Acceleration (a) = (v-u)/t and so (v-u) = at 
Therefore,
Distance travelled (s) = ut + ½ (v-u)t = ut + ½ (at)t = ut + ½ at²
Thus,proved.