Question

S: v2 = u2 + 2as.
is #hi1​

Answer 1

${v}^{2} = {u}^{2} + 2as \\ \\ derivation \: is \: here \\ from \: first \: equation \: of \: motion \\ we \: have \: v = u + at \\ \\ Now \ squaring \ on \ both \ side\\\\v^{2}=(u+at)^{2}\\ \\v^{2}=u^{2}+a^{2} t^{2}+2u \ at\\\\v^{2}=u^{2}+2a(\frac{1}{2}at^{2}+ut) \ (take \ 2a \ common )\\\\we \ know \ that \ s=ut+\frac{1}{2}at^{2}\\ \\puttting \ value \ of \ s \ here\\\\v^{2}=u^{2}+2as\\ \\Hope \ it \ is \ clear \ to \ you$

Answer 2

Answer:

Explanation:

So i am having a slight problem deriving this equation.

there is a simple way which is

v=u+at ->

t = v-u/a s = (v+u)t/2

so s = (v+u)*(v-u)/2a

2as = (v+u)(v-u)

2as = v2-u2 v2=u2+2as