Question

s wooden log is diplased to a distance of 20m in 10 second by applying 500 N effort. Calculate the work done and power.
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Answer 1

Answer:

Weight of block in direction of the incline= 2sin15 kN= 0.52 kN (since weight of block acts downward)

W= Fs= 0.52(10)= 5.17 kJ

so work done is 5.17 kJ.

Explanation:

I HOPE MY ANSWER IS CORRECT